Pumped Hydro Storage Sizing Calculator

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Harnessing gravity with pumped hydro

Pumped-storage hydropower (PSH) is the most widely deployed form of large-scale, long-lifetime electricity storage. It works by moving water between two reservoirs at different elevations:

This calculator provides a quick, transparent sizing estimate from four inputs:

What the calculator outputs (and how to read it)

Given your inputs, the tool estimates:

Important: the power shown is an average over the discharge duration. Real plants have operating ranges (minimum/maximum turbine flow, ramping constraints, and grid dispatch variability), so instantaneous power may differ.

Equations used

The core physics is gravitational potential energy. Using water density ρ ≈ 1000 kg/m³ and gravitational acceleration g ≈ 9.81 m/s²:

1) Gross potential energy (joules):

Egross = ρ g h V

2) Convert joules to MWh:

1 MWh = 3.6×109 J ⇒ Egross,MWh = Egross / (3.6×109)

3) Apply round-trip efficiency to estimate deliverable electrical energy:

Edelivered = Egross,MWh × η

where η is the round-trip efficiency as a decimal (e.g., 75% → 0.75).

4) Average discharge power over duration T:

Pavg (MW) = Edelivered (MWh) / T (h)

5) Average flow rate to move the usable volume over time:

Q (m³/s) = V (m³) / [T (h) × 3600 (s/h)]

MathML (same relationships, unambiguous formatting)

E=ρghV E_gross,MWh=E3.6×109 E_delivered=E_gross,MWhη P_avg=E_deliveredT Q=VT×3600

Note on efficiency terminology: “Round-trip efficiency” normally refers to energy out (electricity generated) divided by energy in (electricity used to pump) over a full cycle. This calculator uses it as a simple derating factor on gross stored potential energy to estimate deliverable electrical energy. That is appropriate for quick sizing, but project studies often separate pumping efficiency, turbine efficiency, generator/motor efficiency, transformer losses, and hydraulic losses.

Worked example

Inputs (matching the default example on the page):

Step 1 — Gross potential energy:

Egross = 1000 × 9.81 × 100 × 100000 ≈ 9.81×1010 J

Egross,MWh ≈ (9.81×1010) / (3.6×109) ≈ 27.25 MWh

Step 2 — Deliverable electrical energy:

Edelivered ≈ 27.25 × 0.75 ≈ 20.44 MWh

Step 3 — Average discharge power over 6 hours:

Pavg ≈ 20.44 / 6 ≈ 3.41 MW

Step 4 — Average flow rate:

Q ≈ 100000 / (6 × 3600) ≈ 4.63 m³/s

That flow corresponds to a mass flow of ṁ = ρQ ≈ 1000 × 4.63 ≈ 4630 kg/s.

Comparison table: how inputs move the outputs

The relationships are linear in volume and head, and linear in efficiency for deliverable energy and power. Duration only affects power and flow (not total energy).

Input changed Energy (MWh) Avg power (MW) for fixed duration Flow (m³/s) for fixed duration
Increase usable volume V Increases proportionally Increases proportionally Increases proportionally
Increase head h Increases proportionally Increases proportionally No change (volume/time)
Increase efficiency η Increases proportionally (deliverable) Increases proportionally No change (volume/time)
Increase duration T No change Decreases (same energy spread over more hours) Decreases (same volume spread over more time)

Interpreting results in practice

Assumptions & limitations (read before using for design)

If you want a quick sanity check: typical round-trip efficiency values are often in the ~65–85% range depending on equipment and operating conditions, and practical heads vary widely (from tens of meters to several hundred meters). Use your site-specific data whenever possible.

Enter values to compute energy and flow.

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