Motional EMF

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Motional electromotive force (motional EMF) is the voltage induced when a conductor moves through a magnetic field. Charges in the conductor experience the magnetic part of the Lorentz force, separate along the conductor, and create an electric field that produces a measurable potential difference (voltage) between the ends. This is the same physical idea used inside many generators: mechanical motion is converted into electrical energy.

What this calculator computes

This calculator uses the standard motional-EMF magnitude formula for a straight conductor moving in a uniform magnetic field:

ε = B L v sin ( θ )

The sin(θ) term comes from the fact that only the component of velocity perpendicular to the magnetic field contributes. If the conductor moves parallel to the field lines, it does not “cut” field lines and the induced EMF magnitude goes to zero.

Where the formula comes from (brief derivation)

For a charge q moving with the conductor at velocity v through a magnetic field B, the magnetic force is:

Fmag = q(v × B)

In a straight rod, this force drives positive and negative charges toward opposite ends, creating an internal electric field E. At equilibrium, electric and magnetic forces balance in magnitude:

qE = qvB sin(θ) ⇒ E = vB sin(θ)

The potential difference between the ends of a rod of length L is then:

ε = EL = BLv sin(θ)

This is also consistent with Faraday’s law when the moving conductor forms part of a closed circuit (for example, a sliding rod on rails), because the motion changes the area of the loop and therefore changes magnetic flux through the loop.

How to use the calculator

  1. Enter B in tesla (T).
  2. Enter the effective conductor length L in meters (m).
  3. Enter the speed v in meters per second (m/s).
  4. Enter the angle θ (degrees) between the direction of motion and the magnetic field direction. Use 90° for perpendicular motion.
  5. Click Compute to get the induced EMF in volts (V).

Interpreting the result

Worked example

Problem: A 0.50 m rod moves at 3.0 m/s through a uniform 0.80 T magnetic field. The angle between v and B is 60°. Find the motional EMF magnitude.

ε = (0.80)(0.50)(3.0)(0.866) ≈ 1.04 V

Interpretation: Under these conditions, the rod develops about 1.0 volt between its ends. If it completes a circuit, current will flow with a direction set by Lenz’s law and the geometry.

Quick reference: sin(θ) for common angles

Angle θ (degrees) sin(θ) Effect on EMF
0 No induced EMF (motion parallel to B)
30° 0.5 Half the maximum EMF
45° 0.707 About 71% of maximum
60° 0.866 About 87% of maximum
90° 1 Maximum EMF (motion perpendicular to B)

Assumptions and limitations

References (for further reading)

Enter values and press compute.

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